2x^2+(p+1)x+8=0

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Solution for 2x^2+(p+1)x+8=0 equation:


Simplifying
2x2 + (p + 1) * x + 8 = 0

Reorder the terms:
2x2 + (1 + p) * x + 8 = 0

Reorder the terms for easier multiplication:
2x2 + x(1 + p) + 8 = 0
2x2 + (1 * x + p * x) + 8 = 0

Reorder the terms:
2x2 + (px + 1x) + 8 = 0
2x2 + (px + 1x) + 8 = 0

Reorder the terms:
8 + px + 1x + 2x2 = 0

Solving
8 + px + 1x + 2x2 = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + px + 1x + -8 + 2x2 = 0 + -8

Reorder the terms:
8 + -8 + px + 1x + 2x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + px + 1x + 2x2 = 0 + -8
px + 1x + 2x2 = 0 + -8

Combine like terms: 0 + -8 = -8
px + 1x + 2x2 = -8

Add '-1x' to each side of the equation.
px + 1x + -1x + 2x2 = -8 + -1x

Combine like terms: 1x + -1x = 0
px + 0 + 2x2 = -8 + -1x
px + 2x2 = -8 + -1x

Add '-2x2' to each side of the equation.
px + 2x2 + -2x2 = -8 + -1x + -2x2

Combine like terms: 2x2 + -2x2 = 0
px + 0 = -8 + -1x + -2x2
px = -8 + -1x + -2x2

Divide each side by 'x'.
p = -8x-1 + -1 + -2x

Simplifying
p = -8x-1 + -1 + -2x

Reorder the terms:
p = -1 + -8x-1 + -2x

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